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How to create a table with 180+ fields?
Message
General information
Forum:
Microsoft SQL Server
Category:
SQL syntax
Environment versions
SQL Server:
SQL Server 2008 R2
Application:
Web
Miscellaneous
Thread ID:
01600848
Message ID:
01600883
Views:
19
Ok with the help from a guy at Expert Exchange i have it running correctly. Still, i need to save the result to a table in my db ( i delete it prior to running the pivot ) but tried entering INTO myPivot in my dynamic query and it triggers a syntax error. This is the script:
SELECT @DynamicPivotQuery =
N'SELECT Station, CarGroup, CarNo,' + @ColumnName +
'FROM
(
	SELECT R.PickUpStation as Station, R.CarGroup, R.CarNo, REPLACE(CONVERT(VARCHAR(6), D.[Date], 100), '' '', '''') AS DateString
	FROM dbo.FleetTrack AS R
	INNER JOIN #Date AS D
		ON R.PickUpDate <= D.[Date]
		AND R.DropOffDate >= D.[Date]
	) AS Reservation
PIVOT
(
	COUNT(DateString)
	FOR DateString IN (' + @ColumnName + ')
) AS pvt
ORDER BY pvt.Station, pvt.CarGroup, pvt.CarNo'

EXECUTE sp_executesql @DynamicPivotQuery;
How do i create a table into my DB with the results of the above ? ( in pvt )





>Hi
>I need to create a table with 2 character fields ( field1, field2 ) then fields of BIT type, default to 0 (false) , named
>[0501], [0502] [0503].....and up to [1029], [1030], [1031]
>Where 0501 represents May 1, etc... ( format mmdd)
>Is there some way to program sql server to build this?
>
>Thanks
>Jaime
Why do programs stop working correctly as soon as you leave the Fox?
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