Sorry, Naomi, I read as just one could be specified.

if (item.prCtr1 != 0 && ("|"+[item.prCtr2, item.prCtr3, item.prCtr4, item.prCtr5, item.prCtr6].join("|") + "|").indexOf("|" + item.prCtr1 + "|") != -1){
   errorMsg = resourceFactory.getResource('Messages', 'allDifferentProfitCenters')
}

and the rest follows...

This is rather obscure, but, errr, it probably works...

>Hi Antonio,
>
>I am not exactly sure about your answer. Here is my current method implementation - I want to make sure that all selected profit centers are different (e.g. I didn't select the same center twice in case I selected it)
>
>

>if ((item.prCtr1!=0 && (item.prCtr1 == item.prCtr2 || item.prCtr1== item.prCtr3 
>                         || item.prCtr1 == item.prCtr4 || item.prCtr1 == item.prCtr5 || item.prCtr1 == item.prCtr6))
>                         || 
>                         (item.prCtr2!=0 && (item.prCtr1 == item.prCtr2 || item.prCtr2== item.prCtr3 
>                         || item.prCtr2 == item.prCtr4 || item.prCtr2 == item.prCtr5 || item.prCtr2 == item.prCtr6))
>                         ||
>                         (item.prCtr3!=0 && (item.prCtr3 == item.prCtr1 || item.prCtr3== item.prCtr2 
>                         || item.prCtr3 == item.prCtr4 || item.prCtr3 == item.prCtr5 || item.prCtr3 == item.prCtr6))
>                         || 
>                         (item.prCtr4!=0 && (item.prCtr4 == item.prCtr1 || item.prCtr4== item.prCtr2 
>                         || item.prCtr4 == item.prCtr3 || item.prCtr4 == item.prCtr5 || item.prCtr4 == item.prCtr6))
>                         ||
>                         (item.prCtr5!=0 && (item.prCtr5 == item.prCtr1 || item.prCtr5== item.prCtr2 
>                         || item.prCtr5 == item.prCtr3 || item.prCtr5 == item.prCtr4 || item.prCtr5 == item.prCtr6))
>                         ||
>                         (item.prCtr6!=0 && (item.prCtr6 == item.prCtr1 || item.prCtr6== item.prCtr2 
>                         || item.prCtr6 == item.prCtr3 || item.prCtr6 == item.prCtr4 || item.prCtr6 == item.prCtr5)))
>
>                     {
>                         errorMsg = resourceFactory.getResource('Messages', 'allDifferentProfitCenters')
>                     }

>
>>

>>parseFloat([0,item.prCtr2, item.prCtr3, item.prCtr4, item.prCtr5, item.prCtr6].join(""))
>>

>>
>>will be 0 if no other profit center but item.prCtr1 is specified.
>>
>>>Hi everybody,
>>>
>>>I found this page
>>>
>>>https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/in
>>>
>>>I am writing a function for checking profit centers. An item can have 6 profit centers. The values are saved as item.prCtr1, item.prCtr2, etc.
>>>
>>>I want to make sure that if they are specified (e.g. not 0/null), then they are all different.
>>>
>>>So, I am going to write like this
>>>
>>>

>>>if (item.prCtr1!=0 && item.prCtr1 in new Array(item.prCtr2, item.prCtr3, item.prCtr4, item.prCtr5, item.prCtr6) )

>>>
>>>The problem here that according to that reference, it will also compare with the array's index and so I may get false positives.
>>>
>>>Do you see a way to write the above code in a simple manner? Or I'd rather write 5 OR checks for all 6 of them?
>>>
>>>What do you think?
>>>
>>>Thanks in advance.