isn't there a problem with first element of sorted array?
hold = [3,9,0,4,7]
vs.
hold = [3,9,2,4,7]

>And a bit clearer, now, by adding a test function to the object (or to its class):
>
>

>item.hasDuplicateCenters = function(){
>	var hold = [this.prCtr1, this.prCtr2, this.prCtr3, this.prCtr4, this.prCtr5, this.prCtr6];
>	hold.sort();
>	for (var index = 5; index > 0; index--){
>		if (hold[index] != 0){
>			if (hold[index] === hold[index - 1]) return true;
>		} else return false;
>	}
>
>	return false;
>}
>
>
>if (item.hasDuplicateCenters())
>	errorMsg = resourceFactory.getResource('Messages', 'allDifferentProfitCenters')
>

>
>>Hi Antonio,
>>
>>I am not exactly sure about your answer. Here is my current method implementation - I want to make sure that all selected profit centers are different (e.g. I didn't select the same center twice in case I selected it)
>>
>>

>>if ((item.prCtr1!=0 && (item.prCtr1 == item.prCtr2 || item.prCtr1== item.prCtr3 
>>                         || item.prCtr1 == item.prCtr4 || item.prCtr1 == item.prCtr5 || item.prCtr1 == item.prCtr6))
>>                         || 
>>                         (item.prCtr2!=0 && (item.prCtr1 == item.prCtr2 || item.prCtr2== item.prCtr3 
>>                         || item.prCtr2 == item.prCtr4 || item.prCtr2 == item.prCtr5 || item.prCtr2 == item.prCtr6))
>>                         ||
>>                         (item.prCtr3!=0 && (item.prCtr3 == item.prCtr1 || item.prCtr3== item.prCtr2 
>>                         || item.prCtr3 == item.prCtr4 || item.prCtr3 == item.prCtr5 || item.prCtr3 == item.prCtr6))
>>                         || 
>>                         (item.prCtr4!=0 && (item.prCtr4 == item.prCtr1 || item.prCtr4== item.prCtr2 
>>                         || item.prCtr4 == item.prCtr3 || item.prCtr4 == item.prCtr5 || item.prCtr4 == item.prCtr6))
>>                         ||
>>                         (item.prCtr5!=0 && (item.prCtr5 == item.prCtr1 || item.prCtr5== item.prCtr2 
>>                         || item.prCtr5 == item.prCtr3 || item.prCtr5 == item.prCtr4 || item.prCtr5 == item.prCtr6))
>>                         ||
>>                         (item.prCtr6!=0 && (item.prCtr6 == item.prCtr1 || item.prCtr6== item.prCtr2 
>>                         || item.prCtr6 == item.prCtr3 || item.prCtr6 == item.prCtr4 || item.prCtr6 == item.prCtr5)))
>>
>>                     {
>>                         errorMsg = resourceFactory.getResource('Messages', 'allDifferentProfitCenters')
>>                     }

>>
>>>

>>>parseFloat([0,item.prCtr2, item.prCtr3, item.prCtr4, item.prCtr5, item.prCtr6].join(""))
>>>

>>>
>>>will be 0 if no other profit center but item.prCtr1 is specified.
>>>
>>>>Hi everybody,
>>>>
>>>>I found this page
>>>>
>>>>https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/in
>>>>
>>>>I am writing a function for checking profit centers. An item can have 6 profit centers. The values are saved as item.prCtr1, item.prCtr2, etc.
>>>>
>>>>I want to make sure that if they are specified (e.g. not 0/null), then they are all different.
>>>>
>>>>So, I am going to write like this
>>>>
>>>>

>>>>if (item.prCtr1!=0 && item.prCtr1 in new Array(item.prCtr2, item.prCtr3, item.prCtr4, item.prCtr5, item.prCtr6) )

>>>>
>>>>The problem here that according to that reference, it will also compare with the array's index and so I may get false positives.
>>>>
>>>>Do you see a way to write the above code in a simple manner? Or I'd rather write 5 OR checks for all 6 of them?
>>>>
>>>>What do you think?
>>>>
>>>>Thanks in advance.