This will fail on the 5;03;10

but I guess I can do it from here. Antonios Code looks very nice for the transform and I will get an idea about the number of chgaracters per group.

Thank you (_ _)

>

>TEXT TO lcx NOSHOW  
>1
>10
>2
>03
>1.1
>12.R
>1.1.R
>1201.1.RBX.250.R.1
>1.R
>1.R.1
>A
>B
>AA
>5.R
>CDXB
>ENDTEXT &&lcx 
>
>STRTOFILE(lcx,'xyz.tmp')
>
>CREATE CURSOR curXYZ (cField c(40), cSortFld c(240))
>APPEND FROM xyz.tmp DELIMITED WITH TAB
>DELETE FILE xyz.tmp
>
>replace ALL cSortFld WITH IP_Ascii (cField)
>INDEX on cSortFld TAG cSortFld
>browse
>
>
>FUNCTION IP_ASCII(tcRow)
>LOCAL lnColLen, lnMaxCol, lnColCnt, laCols[1], lcErg, lcAdd, luCol
>lnColLen = 5
>lnMaxCol = 7
>lnColCnt = ALINES(laCols, UPPER(tcRow),1,".")
>lcErg = ""
>FOR lnCurCol = 1 TO lnMaxCol
>   lcAdd = IIF(lnColCnt>=lnCurCol,laCols[lnCurCol], "")
>    lcErg = m.lcErg + PADL(m.lcAdd, m.lnColLen, iif (EMPTY(m.lcAdd), CHR(45), IIF(ISAlpha(m.lcAdd), CHR(64), CHR(47)))) + "." 
>next
>RETURN m.lcErg
>
>