Plateforme Level Extreme
Abonnement
Profil corporatif
Produits & Services
Support
Légal
English
SQL breakdown of data
Message
Information générale
Forum:
Visual FoxPro
Catégorie:
Codage, syntaxe et commandes
Divers
Thread ID:
01648857
Message ID:
01648864
Vues:
85
>>>>>Hello,
>>>>>
>>>>>I have a table with 1,500 records and with one column: ID, comprised of numeric data ranging from 1 - 1,591. As the
>>>>>numbers get higher, the frequency of their appearance increases. But what's important, is not so much any given value
>>>>>but how many numbers appear within a given range. And yes, I am trying to figure out a cutoff point that will separate
>>>>>this table into the numbers that appear with the highest frequency (they happen to be larger numbers, in this table)
>>>>>and numbers that appear less frequently (they happen to be smaller numbers.)
>>>>>So, I want to know if certain values appear more often than others, kind of like a heat map, except the response would
>>>>>be in a tabular form rather than in graphic.. Is there a way to use an SQL statement to do this? Can I preselect
>>>>>the number of ranges and their size, for example: break the table up into 20 ranges. But I can't know
>>>>>which values each of the 20 ranges will have in advance? I know it's a vague question but I wondered
>>>>>what you all might say as this kind of question is coming up a lot.
>>>>>
>>>>>Thank you,
>>>>>Steve
>>>>
>>>>Hi, Steve,
>>>>
>>>>Can you post the table structure (at least for the relevant columns)?
>>>
>>>table name: MY_IDS
>>>field name: ID
>>>data type: numeric
>>>range of values in ID: 1 - 1,591
>>>number of rows: 1,500
>>>
>>>(I tried to upload the dbf but the system won't allow it.)
>>
>>Try
>>
>>;with counts as (select Id, count(Id) as frequency
>>from My_IDS
>>group by Id)
>>
>>select *, NTILE(5) OVER (order by Frequency)
>>from counts -- group into 5 different buckets in order of the frequency
>>
>>The above is for SQL Server.
>
>Naomi, Is the first line missing something, since it begins with:
>
>
>;with counts as (select Id, count(Id) as frequency
>
>
>Thanks, Steve

Am I supposed to start the program with the first line, because I get an error when I do:

;with counts as (select Id, count(Id) as frequency
Précédent
Suivant
Répondre
Fil
Voir

Click here to load this message in the networking platform