>>Hi,
>>
>>I am writing the code in C# but if I know how to do it in VFP, I can easily convert it to C#. That is, I know C# but weak in math :). And I can do this with a bunch of IF CASE and so on. But I think there should be a more concise formula.
>>
>>nTodayDow - today/current day Day of the week (1 to 7)
>>nDays2Advance - variable that holds the number of days to advance, from the current day. This can be 1 to any reasonable number (e.g. 100). And I want to change the nDays2Advance given that the weekend should be skipped (Saturday and Sunday).
>>Example:
>>nTodayDow = 3 (Wednesday)
>>nDays2Advance = 2
>>So the nDays2Advance = 2 (since the weekend is too far ahead)
>>But if nDays2Advance is 4, then it should be changed to 6, otherwise it will fall on the weekend.
>>
>>How can I express the above in the formula that would help me calculate nDays2Advance?
>>
>>TIA
>
>Thank you everybody who took the time to help me with this problem. The solution I implemented is to set the infinite loop (in C# while {true}), then advancing the date one day at a time. And then checking if the resulting date is Saturday/Sunday; in which case skipping the date. Until reaching the nDays2Advance that does not fall on a weekend.

And I came up with this years ago: http://fox.wikis.com/wc.dll?Wiki~Weekdays~Wiki

A similar solution was posed recently by Pinal Dave for SQL Server.