Dear Sir,

I am using these codes to open whatsapp

Declare  Integer FindWindow In WIN32API String , String
Declare  Integer SetForegroundWindow In WIN32API Integer
Declare  Integer  ShowWindow  In WIN32API Integer , Integer
Declare Integer ShellExecute In shell32.Dll ;
	INTEGER hndWin, ;
	STRING cAction, ;
	STRING cFileName, ;
	STRING cParams, ;
	STRING cDir, ;
	INTEGER nShowWin


cmd='https://web.whatsapp.com'

=ShellExecute(0, 'open', cmd,'', '', 1)

https://web.whatsapp.com/ opens perfectly. No issue

If I run above codes again then a new instance opens
How to know https://web.whatsapp.com/ is already opened?
If found opened already then codes must not open a new instance but go focus to previously opened website.

Regards