Thank you, Luis.
>Hi Dmitry, from what you explained I think this will work:
>
>
>SELECT a.DATE_FLD, a.ORDER_NO, a.FIELD2, a.FIELD3
> FROM MyTable a
> INNER JOIN
> (
> SELECT DATE_FLD, MAX(ORDER_NO) AS ORDER_NO
> FROM MyTable
> GROUP BY DATE_FLD
> ) b ON a.DATE_FLD = b.DATE_FLD AND a.ORDER_NO = b.ORDER_NO
> ORDER BY a.DATE_FLD, a.ORDER_NO
>
>
>I hope this solves your needs.
>
>Luis
>
>>>>Hi,
>>>>
>>>>I am creating a SQL Select that will select ONE record based on two fields. The two fields are DATE_FLD and ORDER_NO field. There could be more than one records with the same DATE_FLD value (e.g. "01/01/2023) but the ORDER_NO will be different for each record. I need to select a record with the largest value in the ORDER_NO field.
>>>>
>>>>Here is my test:
>>>>
>>>>select TOP 1 CONVERT(VARCHAR(10),DATE_FLD,101) + STR(ORDER_NO), FIELD2, FIELD3 from MyTable order by DATE_FLD, ORDER_NO DESC
>>>>
>>>>
>>>>Will the above give me what I am looking for?
>>>>
>>>>TIA
>>>>
>>>>UPDATE. I think the problem I have is defining the ORDER BY clause correctly. What am I missing?
"The creative process is nothing but a series of crises." Isaac Bashevis Singer
"My experience is that as soon as people are old enough to know better, they don't know anything at all." Oscar Wilde
"If a nation values anything more than freedom, it will lose its freedom; and the irony of it is that if it is comfort or money that it values more, it will lose that too." W.Somerset Maugham