>>>>Hi,
>>>>
>>>>Can you programmatically close a modal form when a user clicks anywhere outside the form?
>>>
>>>Shouldn't form's .deactivate() event fire then?
>>
>>When making the form modeless, clicking outside the form indeed closes the form. And I can determine that the form .deactivate is called.
>>Do you suggest to set the form reference to NULL in deactivate()? So that not to have what I believe is called "dangling" references?
>>
>>UPDATE. The code that runs upon a user clicking on a button of the menu form, is based on the form tag value. That is, the tag is set to '1' when user clicks on the 1st button, and so on.
>>Now, when the form is deactivated, the value of Tag is gone.
>>How do I pass the value of selected button to the called method?
>
>Old trick... you instantiate the form from a class and assign to a variable. Then have your buttons only .hide() the form, not close it. Then in the calling code you still have a reference to your form, can access its properties. Then you can release the variable when done (or if it's a local one, do nothing, it'll release when the code exits).

Sorry I am not getting it. Again, in my case - now - the popup form is MODELESS. As soon as the code in this, POPUP MODELESS form, calls .hide(), the method DEACTIVATE is fired. And therefore, the .tag is gone. That is, as soon as hide() fires, the code (in the debugger) goes to the READ EVENTS line.