Hi Don,

Sorry for the confusion in my answer. Yes, I did try your function and it worked perfectly. I did develop a solution for the problem that only used one line of code after reading your reply. Many thanks for the code and the reply.

Thanks

>John,
>From the last reply, I didn't understand if you have your solution or not... Did you try the function I wrote... I will to whatever precision going out that you need. That is what the 3 parameters are for...
>
>Original number, Precision increment value (.002, .000006, .25, .7, whatever), and the length of precision ie: .002 = 3 decimals...
>
>The function is generic enough to handle multiple calls in case you have a variety of controls that require different precision factors.