>I can't remember how to solve this problem
>
>y=(x+3)*(x+24)
>
>if you have y, how do you solve for x
x^2+27x+(3*24-y)=0
let a= 1, b= 27 and c= 3*24-y
sqr= square root, ^ to the power of
then x= (-b+sqr(b^2-4*a*c))/2a
or x= (-b-sqr(b^2-4*a*c))/2a
OK like that?
Regards,
Marc
If things have the tendency to go your way, do not worry. It won't last. Jules Renard.
