Hi John,

nSteps= int(nArc/nAngle)
nAngle1= nArc/nSteps

in your example, nSteps= 153, nArc= 360 and nAngle= 2.347678. nAngle1= 2.352941.

nAngle1 being the corrected angle.

Now assuming you work with numerics with 6 behind the decimal point, you could do the following

nSteps0= int(nArc/nAngle)
lFlipFlop= .t.
n= 0
do while .t.
   nSteps= iif(lFlipflop,n,-n)
   if nSteps= 0  &&  we hope this won't happen :)
       error
   endif
   nAngle1= nArc/nSteps
   if abs(nArc-nSteps*nAngle1)<0.000001
       exit && nSteps and nAngle1 are the information you're looking for
   endif
   lFlipflop= !lFlipflop
   if !lFlipFlop
      n= n+1
   endif

enddo

This way you will try 153, 152, 154, 155 until you find that the product of nSteps and nAngle1 come within the range you want.

HTH,

Marc

>I need to figure out how to divide a number and not have a remainder. I can decrease the divisor by small amounts until it will go evenly. I would like to stay within 6 decmil places. The number I divide will between 0.000001 and 360.000000. The divisor will always be less than 1/4 of the number being divided.
>
>For example my arc is 360.000000 degrees and the angle is 10.00000. This will give me exactly 36 steps for the circle. So if I have an arc of 360.000000 and an angle of 2.347678 I get 153.343005 steps. If I round the steps to 153 I get 2.352941 degrees per step. If I then multiply the step angle by the steps I get less than 360 degrees which is the final angle. The step angle must end up at he final angle exactly.
>
>360.000000 / 2.347678 = 153.343005 Steps
>360.000000 / 153 = 2.352941 Degrees per step
>153 * 2.352941 = 359.999973 Final angle
>
>Thanks for any help