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Help from any mathmetician
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Forum:
Visual FoxPro
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Other
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Thread ID:
00017699
Message ID:
00018140
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52
>>which can have none, 1 or 2 solutions, depending on a, b, c. (In fact, if we're looking for a complex solution, there is always at least one.)
>>
>Re: ax**2 + bx + c = 0, standard form.

I wrote: aX^2+bX+c=0. It's exactly the same thing. :) It's just a different notation.

>And I might add, for applied solutions you might just want to do a "Discriminant" check, if b**2 - 4*a*c < 0, there are no real solutions, only an imaginary pair.

So, where's the difference between what I said and this one? The number of solutions in complex?

Any real number is also a complex one. (The set of complex numbers includes the set of real numbers). So, if you're looking for solutions in complex, you can have 1 or 2 solutions. If there's only one (the discriminant = 0), you're right, the solution has only real part. But that doesn't mean is not a complex one.

>Go back and check your data. (say, what website is this, anyway? :~))

Sorry, it's in my head and "he" doesn't have a direct connection to Internet. :)

Vlad
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