Level Extreme platform
Subscription
Corporate profile
Products & Services
Support
Legal
Français
Invalid key lenght
Message
General information
Forum:
Visual FoxPro
Category:
Coding, syntax & commands
Miscellaneous
Thread ID:
00021912
Message ID:
00021980
Views:
44
>>I get the error 'Invalid key length' when :
>>
>>select a.ADDRESS1,a.ADDRESS2 from DONOR a group by a.ADDRESS1,a.ADDRESS2 having count(*)>1 into cursor temp
>>
>>select a.ADDRESS1 as ADDRESS1 from DONOR a ,temp b where a.ADDRESS1=b.ADDRESS1 and a.ADDRESS2=b.ADDRESS2 order by a.ADDRESS1,a.ADDRESS2 into cursor result
>>
>>I attemp to find out record with duplicate value of address1 and address2.
>>The error locate at the second select statment.
>>I have try
>>- reindex the donor table
>>- add 'where .t.' at the first select statement
>>but still get the error. Why?
>>
>>Info: Address1 and Address2 are character fields of length 50.
>>
>>Thanks
>>-Jasper
>
>Jasper: Don't you have to have an ADDRESS2 field in your second select. All the fields in your ORDER BY clause must be in your SELECT clause:
>
>
>select a.ADDRESS1 as ADDRESS1;
>a.ADDRESS2 as ADDRESS2;
>from DONOR a ,temp b where a.ADDRESS1=b.ADDRESS1 and a.ADDRESS2=b.ADDRESS2 order by a.ADDRESS1,a.ADDRESS2 into cursor result
>
>
>Note the second line.
>
>HTH
>Barbara

I still get the error even :

select a.ADDRESS1,a.ADDRESS2 from DONOR a where .t. group by a.ADDRESS1,a.ADDRESS2 having count(*)>1 into cursor temp

select a.ADDRESS1 as ADDRESS1 ,a.ADDRESS2 as ADDRESS2 from DONOR a ,temp b where a.ADDRESS1=b.ADDRESS1 and a.ADDRESS2=b.ADDRESS2 order by a.ADDRESS1,a.ADDRESS2 into cursor result

I don't know why????
Please help me .....
oh, what is the fastest way to write good program?
Previous
Next
Reply
Map
View

Click here to load this message in the networking platform