Oh, posh! < bg >
You all seem to be insisting on a whole lot more work than is necessary.
If you run a character string thru VAL() and end up with a non-zero number, you have a number without any distracting inner characters.
x='2.5ab3'
y=val(x) ?y
So if you have a string with a number that could be imbedded, you just have to strip off leading chars to get to it.
I'd say Craig's suggestion would be needed if you want to find more than one imbedded number.
