>I have created a app using VFP 6.0 (SP3) and my customer is running it on a Pentium 75. The app starts slowly and if the user double clicks the shortcut icon a second time, they get an error message. The message is "access denied". I understand that a table was open exclusivly by the first execution and that's why I'm getting the error message. This is a standalone app and they should only start the app one time.
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>Is there a way to prevent the user from starting the app a second time?
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>Thanks
>Mark Parker
>MAP Software, Inc.

Hi Mark,

In addition to what you've been told, check out my reply to Edgar Bolton in the Visual FoxPro in General section on 8/6/99. (Message #250977). There's code there related to my "Create Single Instance Applications" article that appeared in the November, 1998 issue of FoxPro Advisor. The complete article is available on-line at the Advisor web site.