It was my understanding that VARTYPE would only pass an 'O' if the variable was a living object. If VARTYPE were to classify a dead object it would return an 'X' because the variable was NULL.

Glenn

>I am sure you know John, but hust to clarify-
>
>the test below will determine if the variable named oMyObject is of the object type, but does not test to see if it actually references a living object. To do that, you either need to check the type of one of the object's properties (usually "name"), or, after testing the type, checking for ISNULL(oMyObject)
>
>>Hi Jim,
>>
>>IF VARTYPE(oMyObject) = "O" && It's an object
>>IF VARTYPE(oMyObject) = "U" && It ain't nothing yet
>>
>>>I am using the addobject method to add an object to my form from a custom container class. Once it is created, how can test to see if it already exists?
>>>
>>>Thanks
>>>Jim Oswald
>>>joswald@innova.net