Hello,
I get an error message, which I cannot interpret, and I don't know what I can do about this.
I have a table, from which I create a view. I use this table again with a different alias, (all on the same screen), and I make a cursor from this alias.
The abovementioned error message occurs, while attempting to run the SQL statement.
Is the problem the view, which is still open?
Any ideas?
Thanks for your time.
Christian Isberner
Software Consultant