>>>>>>my_amt = 12.45
>>>>>>my_amt = str(my_amt)
>>>>>>
>>>>>>When I change my dollar amount of 12.45 to a string, I loose the
>>>>>>decimal point values. When I do a (?my_amt) it shows the 12
>>>>>>and I loose the .45.. Could someone tell me what happend to the
>>>>>>deciaml values?
>>>>>
>>>>>Hi Robert,
>>>>>
>>>>>In VFP 6.0, use:
>>>>>? TRANSFORM(my_amt)
>>>>>* Or
>>>>>? TRANSFORM(my_amt, "@$")
>>>>--------
>>>>Hi George - nice to hear from you again..
>>>>What I need to do is take a number (12.45) and
>>>>strip out the "." to make 1245, then show the implied
>>>>deciaml place. When I am finished, it should look like...
>>>>000012450 - this would be float data type of 6.3 - thanks
>>>
>>>Hi Rob,
>>>
>>>Nice to hear from you too.
>>
>>Whoops, make that--
>>

lcstring = TRANSFORM(my_amt)
>>lcstring = CHRTRAN(lcstring, ".", "")
>>lcstring = PADL(lcstring, 8, "0")
>>lcstring = PADR(lcstring, 9, "0")

Duh!
>---- thanks... the PADR does not work. I can not get the
>"0"'s to go were there are blanks..

Hi Rob,

The reason is there are spaces. Better is this:

lcstring = STR(my_amt, 10, 3)
lcstring = CHRTRAN(ALLTRIM(lcstring), ".", "")
lcstring = PADL(lcstring, 9, "0")

I never can remember about those parameters for the STR() function< g >.