Joege:
Forget my previous reply ... You were right: IT WORKED!
Instead of EVAL('&m'), I guess you were saying just use &m.

m = "THISFORM.lAccessed3 = .T."
&m

THIS WORKS!!

Thanks Jorge

Mal

>I think what you're doing here is evaluating the expression THISFORM.lAccessed3 = .T. like in
>
>

>
>if THISFORM.lAccessed3 = .T.
>..
>endif
>
>

>
>In other words you are asking Is THISFORM.lAccessed3 = .T.?, so when evaluated it tells you if it is or of it isn't, try this:
>
>? eval("THISFORM.lAccessed3 = .T.")
>
>It should return .t. or .f., but no data is changed. Now, to do what you want you just need:
>
>&m
>
>"m" will be substituted at runtime with THISFORM.lAccessed3 = .T., and will be executed as expected, hope I was clear enough
>
>
>
>>
>>Actually, this is what I'm trying to do.
>>
>>m = ALLTRIM('lAccessed' + '3')
>>*need to do this becuase the '3' changes depending on what the form number it's executed from (in this case it's form #3).
>>
>>m = 'THISFORM.' + m + ' = .T.'
>>
>>?m .... && shows THISFORM.lAccessed3 = .T.
>>
>>EVALUATE('m') does not change the lAccess3 to .T.
>>
>>What am I missing? It works for procedures and functions;
>>i.e. if m equaled THISFORM.DoChanges(3).
>>
>>As always, thank you for your help.
>>
>>Mal