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Holiday - brain teaser
Message
De
29/11/1999 00:16:33
 
 
Information générale
Forum:
Politics
Catégorie:
Autre
Divers
Thread ID:
00295415
Message ID:
00296271
Vues:
38
>>>
>>>You have three cards. One ace. Two Jacks. You are trying to get the ace. There are nine possible scenarios based on which card you pick but I will only cover three.
>>>
>>>1.
>>> 1 2 3
>>> A J J
>>>
>>>2.
>>> 1 2 3
>>> J A J
>>>
>>>3.
>>> 1 2 3
>>> J J A
>>>
>>>We will automatically switch each time.
>>>I will assume you take card #1 without looking at it.
>>>
>>>In the first example, I show you #2, you pick #3. You get a J and lose.
>>>In the second example, I show you #3, you pick #2. You get an A and win.
>>>In the third example, I show you #2, you pick #3. You get an A and win.
>>> _
>>>That's 2/3 or 66.6. Try it yourself with cards, if you don't believe it. I know it seems like it should be a 50/50 shot, but it really is 2/3.
>>
>>Sorry, Dan, you're wrong. See my latest reply to Walter Meester. Where you guys are all falling down is in including the result of the already known door in your analysis. The analysis is of 2 doors, not 3; one contains a boat, the other a goat. You own one of the two doors. Therefore the door you already own has a 50% chance of containing the boat. There is no advantage or disadvantage to changing your choice to the other unknown door.
>
>You have to include the other door in the analysis. If it was really 50/50, then the above should give you a 50/50 result. The above gives you a 66.6 result. We are only concerned with the best possible results and what advice to give the player when they choose a door. If you're right then you would tell the player it doesn't make any difference whether you change or not. I say the above example proves that the results will give you a 66.6 result. Take the above example and prove to me that it returns a 50/50 result for the three possibilities.

Sorry again, Dan, but that's exactly what you guys are doing wrong. You're treating it as a 3-door problem. That simply isn't the case - it's a 2-door problem. Opening the first door just gives us the information that it contained one of the 2 goats. The remaining 2 doors contain exactly one boat, and exactly one goat. We "own" one of them; the chance it contains the boat is exactly 50%. There is therefore no advantage in switching your choice to the other remaining door.

This whole thing is starting to remind me of those anonymous E-mails Michael Douglas was getting in "Disclosure" - "Solve the problem."
Regards. Al

"Violence is the last refuge of the incompetent." -- Isaac Asimov
"Never let your sense of morals prevent you from doing what is right." -- Isaac Asimov

Neither a despot, nor a doormat, be

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