Cetin:

Thank you for your reply.

It worked :o)
However :o( ...
When I use the WHERE clause, WHERE Room_No = 1,
the GROUP BY errors out.

What went wrong?

Mal

>>Hi:
>>
>>I have a table:
>>ROOM_NO (int) ... SINGER_NO (int) ... SONG_NO (char)
>>
>>The entire table usually looks like this:
>>ROOM_NO ... SINGER_NO ... SONG_NO
>>3 ...................... 1 ........................ 24
>>1 ...................... 2 ........................ 25
>>1 ...................... 3 ........................ 30
>>2 ...................... 3 ........................ 41
>>1 ...................... 3 ........................ 23
>>2 ...................... 2 ........................ 20
>>2 ...................... 3 ........................ 99
>>2 ...................... 3 ........................ 42
>>1 ...................... 1 ........................ 36
>>1 ...................... 5 ........................ 23
>>3 ...................... 4 ........................ 20
>>2 ...................... 6 ........................ 1
>>
>>Using a WHERE on the Room_No and getting ONE unique set of consecutive Singer_No in Singer_No ORDER. The following is the result I'm looking for.
>>ROOM_NO ... SINGER_NO ... SONG_NO
>>1 ...................... 1 ........................ 36
>>1 ...................... 2 ........................ 25
>>1 ...................... 3 ........................ 30
>>1 ...................... 5 ........................ 30
>>
>>Although Singer_No 1 and 3 are in the table more than once for Room_No 1, I need the first occurance of the singer number only.
>>
>>At first it seemed simple, but I got nowhere :o(
>>
>>Thanks for your help.
>>
>>Mal
>
>

---

select * from mytable ;
>  group by singer_no ;
>  order by room_no, singer_no

Cetin