>QUESTION #1:
>I have been playing with the SELECT command you showed me and I don't understand why the COUNT(*) and the HAVING clause are needed in it. I get the same results (unique records) if I do the following two commands:
>
>SELECT count(*),* FROM mytable GROUP BY field1,field2,field3 HAVING COUNT(*)>1
>-or-
>SELECT * FROM mytable GROUP BY field1,field2,field3
>
>Do you think this is right or am I missing something?
>

Yes, you're missing the fact that Eric's query only returns records that have duplication within the grouping. Just the ones you have to do something about IOW...

IOW, after the query, you have all the non-duplicate records with a COUNT(*) of 1, and anything with more has duplicates.

>QUESTION #2:
>About to copy the records... I am looking for a SELECT command to give me the DUPLICATE records also. The first one was to display the unique records, now I want another command to display the duplicate ones.
>

First:

SELECT COUNT(*) AS NumOccurs, * FROM MyTable ;
   INTO CURSOR AllCounts ;
   GROUP BY <i> field list </i> && This is all distinct records

SELECT * From AllCounts ;
  INTO CURSOR UniqueRecs ;
 WHERE NumOccurs = 1 && non-dups

SELECT * From AllCounts ;
  INTO CURSOR RecsWithDupes ;
 WHERE NumOccurs > 1 && at least one dupe