>Actually, I believe that Dave Frankenbach found this not to be the case recently; the time on STRTRAN() was ~O(n) whereas CHRTRAN() ~O(n^2) on performing substitutions.

Hmm, well in the context of Sean's example:

clear

s = seconds()
for x = 1 to 1000000
	=strtran('smith, charles', ',', '')
endfor
?seconds() - s

s = seconds()
for x = 1 to 1000000
	=chrtran('smith, charles', ',', '')
endfor
?seconds() - s

I always get nearly a third the time. But this is with one occurence and one character, so you are probably correct (whats new? :-), but in Seans question, CHRTran() would be a better faster choice.