>Ok, now, this way is very hard, because i need know the exact bit position for each propiertie, then a look a best solution...

No, each property is a power of two; so to use the example of a setting of 234 and a mask of 128:

? bitand(234,128)


IF BITAND(value,compareconstant) = compareconstant

It helps to RTFM once in a while.