I thought that too - logical isn't it. By adding up the colum.widths my total came to 554. I resized the form (with autoresize controls on it) until all columns displayed fully and the width of the grid was then 591.
Through high-calibre mathematics I deduced that the difference equated to approximately 12 for each of my 3 columns with 1 left over. I had to have a long sleep after that one :)
>
>Why 12? I would have just assumed that:
>
>

nWidth = 0
>for each loColumn in This.Columns
>	nWidth = nWidth + loColumn.Width
>endfor
>?nWidth

>would do it.