>>>I want know the name of the activecontrol.
>>>When i try
>>>
>>>_screen.activeform.activecontrol.name
>>>
>>>returns: grid1
>>>
>>>But what i want is
>>>
>>>_screen.form.pageframe1.page1.grid1
>>>
>>>Is there a way to do this programmaticly
>>>
>
>Oops, I think I just sent an empty message. Sorry. Anyway, try SYS(1272) for what you're looking for:
>
>lcControl = SYS(1272, oObject)
>
>Tamar
Thanks Tamar.
Mike Helland show me a good solution.
But his code is 6 line lenght.
Your solution is only one line.