>>Assume you have information in MyString and sure that USERID is there:
>>TempSting = SUBSTR(MyString, ATC('USERID', MyString)+LEN('USERID'))
>>Result = LEFT(TempSting, AT(' ', TempSting) - 1)
>>
>
>Vlad: When I tried your code I got an empty string returned for the second test condition ("USERIDAA" at end of MyString). Changing 2nd line to
>
>Result = LEFT(TempSting, AT(' ', TempSting + " ") - 1)
>
>seemed to work
>
>............Rich

Correct. I assumed that space always exist in string.

>
>>>I have a string that has ' USERID?? ' somewhere in the string. i want returned the characters directly after the USERID and before the next space or at end of string. 'the is USERIDABC code' I want ABC. 'The USERIDAA' I want AA.
>>>
>>>As always, I have a terrible time with string functions. Have been looking in my Help Character Function Favorites now for 30 minutes and only have a hodge podge of silly looking code.
>>>
>>>Thanks
>>>
>>>Brenda