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Message
From
26/10/2000 02:33:27
 
General information
Forum:
Visual Basic
Category:
Coding, syntax & commands
Title:
Miscellaneous
Thread ID:
00432606
Message ID:
00434440
Views:
17
hi alberto
i have a solution for u i think best in all with the three decimal percision. and real clock accuracy

type the following code to get it

t = ((Timer * 1000) Mod 60000) / 1000

t variable has the value like 39.760

wish u goodluck
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