Andrew,

Actually, this restriction gave me my manager. It's probably incorrect too, since his definition of Median function was wrong.

>Nadya,
>
>>if _tally>3
>> lnMiddleRecord=(_tally/2) && Find middle record
>>else
>> =messagebox('Number of records is less than 3. Can not calculate median...',48)
>
>Where did you find this restriction? My understanding is that the median of two numbers is just the arithmetic mean of those numbers - (n₁+n₂)/2 - and the median of a one number sample is the number itself.
>
>Cheers,
>
>Andrew