>>Hi All,
>>
>>I have a need to develop an algorithm that will
find the center point of 'N' other points. The total number of other points will be from 2 to 5 typically, though it could go up to around 20.
>>
>
>Simply put, your answer lies in averaging the x's, and averaging the y's, and using those averages as your center.
Erik,
Right. Got my answer from larry a coule hours back. Thanks!
I had a case of programmer's disease - I was taking something simple and making it complicated. <g>
Best,
DD
A man is no fool who gives up that which he cannot keep for that which he cannot lose.
Everything I don't understand must be easy!
The difficulty of any task is measured by the capacity of the agent performing the work.
