>What would be the procedure code to open an excel file in a VFP6.0 .prg?
>
>Say the file name I want to open is "c:\temp.xls"


You could do it one of two ways:
1) Use automation. e.g., in Excel 2000 (maybe 98 as well)

oExcel = CreateObject("Excel.Application")
oExcel.Workbooks.Open("c:\temp.xls")
oExcel.Visible = .T.

2) Use the ShellExecute API

Declare Integer ShellExecute ;
    In shell32.dll ;
    Integer nWinHandle, ;
    String cOperation, ;
    String cFileName, ;
    String cParameters, ;
    String cDirectory, ;
    Integer nShowWindow

Declare Integer FindWindow ;
   In win32api ;
   String cNull, String cWinName

ShellExecute(FindWindow(0, _screen.Caption), ;
                    "Open", "c:\temp.xls", ;
                    "", Sys(2023), 1)