>>Hi larry
>>if you still need an other option...
>>
>>dif = (year(date2)-year(date1))*12+(month(date2)-month(date1))
>>
>>Mario
>
>Mario, Glenn and Michael
>IMHO your functions are overseeing the fact that a date also has a day component. With your function it would be at least a month provided months are different. ie :
>date1 = {^2000/01/31}
>date2 = {^2000/02/01}
>Cetin


Hi Celtin,

You are absolutely correct, but the original problem description inferred that days were not a consideration. Perhaps Larry can clear this up.