>With respect - I included the days. Unfortunately, the days bit 'fell off' the submission (HTML tags or something) I repeat it below:
>
>Monthdiff = 12*(year(t1)-year(t2)-1) + month(t1)-month(t2) ;
>- iif(day(t1) < day(t2), 1, 0)
>
>In other words, calculate the months, and reduce the result by one if the day of the second date is less than the day of the first result.
>
>Regards
>
>Mike

Mike,
I didn't comment on yours separately but it's caught too. -1 there seems to be a typo ( consider {^2000/1/1} and {^2001/1/1} ). Other than that yours would work almost with the exception of leap years ( {^2000/02/29} and {^2001/02/28}).
Regards.
Cetin