>I figured out how to use a left outer join to get values in table 1 and any matching records in table 2. there are 4 fields.
>I know how to sum fields 3 and 4 by field 1 (ie select 1 sum(3) as s1 sum(4) as s2 form a order by 1 group by 1 into b).
>
>What I do not see how to do in this step is how to select only records where sum(3) <> sum(4) in the above select.
> I can do it in a subsequent select.
>
>Can it be done?
You should be able to do it with a HAVING clause, e.g.,
... GROUP BY 1 HAVING sum(3)<>sum(4)
Insanity: Doing the same thing over and over and expecting different results.
