>>If the local disk is partitioned, say at 2 gb, then the value returned will correspond to the size of the logical drive, not the physical one. For example, say you have a 4 gb drive divided equally into 2 logical drives, say C: and D:. GetDiskFreeSpaceEx() would only return 2 gb for either. If it's not partitioned, the function should return 4 gb. Unfortunately, I don't have a Win95 box easily available to test. Further, I don't have an NT server to bang it off of either. Maybe tomorrow I can run that test.
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>As far as I know, it's not partitioned. Besides, it doesn't explain, why I got different results from my Windows 95 computer and the server itself. May be somebody else can test it? I know, we had to upgrade long time ago :)

Older boxes (like the one I have at home) that are running Win95 (I'm running Win98SE), couldn't handle a drive larger than 2 gb without a software extension to the ROM BIOS. Perhaps this is the problem. AFAIK, the information regarding the size and free space come from the ROM BIOS which GetDiskFreeSpaceEx() deals with. If the OS doesn't recognize the software extension, that might explain it. I'll try testing tonight on my home machine and report back tomorrow. I do think, however, that I've tried this before and gotten the correct results back.