>>>>

>>>>lcIm = '99999999'
>>>>if ( Thisform.decPlaces != 0 )
>>>> lcIm = Stuff(lcIm, Len(lcIm)-Thisform.decPlaces, 1, '.')
>>>>endif
>>>>

>>>
>>>Ok, I think I've found another solution
>>>
>>>

lcIm = padl(9999999 / 10 ^ Thisform.Decplaces,7) + '9'

>>>
>>>I'm now into questions of readability :(
>>
>>Not quite the same though - it falls over for Decplaces > 2 (your example treated them as the same as Decplaces=0),
>
>Yes I know,
>
>I wanted this for a generic function.. but the example I pulled the Case Statement from was in a form which will only ever go to 2 dp.
>My initial question didn't _Exactly_ specify my requirements, But then again your answer didn't _exactly_ meet my specification either! (not being ungrateful)
>
>I'm still open to suggestions!
>
>Will

for generic - how about the following, where tlen is total length of string & dp is number of decimal places

iff( dp = 0, padl( "", tlen, '9' ), padl( "", tlen-dp-1, '9' ) + "." + padl( "", dp, '9' ) )

with a bit of checking on valid values for tlen & dp