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Using WinZip
Message
From
30/07/2001 16:53:10
 
 
General information
Forum:
Visual FoxPro
Category:
Other
Title:
Miscellaneous
Thread ID:
00527556
Message ID:
00537470
Views:
26
nope. nothing under the path column...

using the msmapi class, the files that are attached are temporily stored in the c:\temp\ directory. once i .fetch() the attachment, I am attempting to extract the zip file....

oVar.ZipFname = allt(m.att_file)

***********oVar.Zipfname equals "c:\temp\z442001.zip"

oVar.WinZipCmndLn = ALLT(oVar.WinZipLoc) + ;
" -e -o " + ;
ALLT(oVar.ZipFname) + " " + ALLT(oVar.ZipTargetPath)

oProcess = CREATEOBJECT("API_APPRUN", allt(oVar.WinZipCmndLn),"","NOR")
oProcess.LaunchAppAndWait()
WAIT CLEAR
oVar.ZipStatus = oProcess.CheckProcessExitCode()
oProcess = .NULL.

RELEASE CLASSLIB PROCESS
Thanks in Advance.

J. Turner
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