It doesn't work when the date is the last day of month and the next month has less than 31 days. Also for January 28, 29, 30.

Vlad

>My suggestion will give you the date of the last day of the month. Simply change it to:
>day( date()+31 - day(date()+31) )
>to get the days.
>
>>date()+31 - day(date()+31) && will do it. Instead of date(), you can send {02/01/98}, for example