>>I already told and everyone already guessed, that 99 have 100% to survive and the last one has 50% probability.
>
>I *THINK* I have it. You have no idea how many different groups of binary numbers I put together trying to see a pattern that can be discernible by a single bit answer.
>
>The last sage says White if there is an even number of white hats ahead of him or black if there is an even number of black hats.
>
>Sage 99 counts the number of black or white hats ahead of him and he can tell immediately if he's black or white.
>
>The rest keep track of the previous answers and so on.
>
>This better be it!
>
>alex

Congrats!!!!!!! :)

Yes, this is my solution.