Hi Pam,
I tried your suggestion, and in this circumstance they return the same thing. The index does change after an item is removed, but in this case the user has selected an item and both ListIndex and ListItemID will return a reference to the selected item.

I didn't figure out why the listbox is losing all the values in the second column when the items are reindexed, but I did find a work around fix using a local array. It looks like this:

LOCAL lnColumn, lcNode, laVitals

DECLARE laVitals[1,2] &&array used to store all the vitals that are not being removed

lcNode = This.List(this.ListIndex, 2) && NodeIndex used to bold and un-bold the node on tree

******************************************************************
**	Scan through listbox and stuff all non-selected vitals in the 
**	array
******************************************************************
lnPosition = 1
FOR i = 1 TO this.ListCount 
	IF !THIS.Selected(i)
		laVitals[lnPosition,1] = THIS.List(i, 1)
		laVitals[lnPosition,2] = THIS.List(i, 2)
		lnPosition = lnPosition + 1		
		DIMENSION laVitals[lnPosition,2]
	ENDIF 
ENDFOR
******************************************************************
**	Un-Bold the corresponding node on the tree
******************************************************************
WITH ThisForm.Ctreeviewctrl1.TREEVIEW.NODES(lcNode)
	.FORECOLOR = RGB(0,0,0)
	.BOLD = .T.
ENDWITH
******************************************************************
**	Clear the listbox of all items
******************************************************************
THIS.Clear()

******************************************************************
**	Stuff the items from the array back in the listbox
******************************************************************
FOR i = 1 TO (ALEN(laVitals,1)- 1)
	THIS.AddListItem(laVitals(i,1),i,1)
	THIS.AddListItem(laVitals(i,2),i,2)
ENDFOR

If there is a better way of doing this I would be very interested to know.
Thanks for your help.

Josh