>
>ROUND( nValue + 0.5)
>
>Will always round up.
Unless nValue is already an integer -- such as 4.0. The ROUND of (4.0+0.5) is 5.0, which I doubt is desirable in this case. You might instead want to go with 0.49 (if that precision is close enough), or use an IIF() statement. (Yes, I know the problems with IIF()s in VB but in this case I doubt that the performance hit will be a real problem:)
ROUND(IIF(ROUND(nValue,0) = nValue, nValue, nValue + 0.5))
The whole problem with the world is that fools and fanatics are always so certain of themselves, but wiser people so full of doubts. - Bertrand Russell
