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WinExec() does not accept a path
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From
28/10/1997 21:30:45
 
 
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Forum:
Visual C++
Category:
Troubleshooting
Title:
WinExec() does not accept a path
Miscellaneous
Thread ID:
00057147
Message ID:
00057147
Views:
77
In Visual C++ 5.0, I have a WinExec() statement used to start an EXE. It goes like this: WinExec('notepad.exe',SW_SHOWNORMAL). This works fine. However, as soon as I try to put a full path, Visual C++ returns an error at build time. I can't do something like this: WinExec('c:\windows\notepad.exe',SW_SHOWNORMAL).
Michel Fournier
Level Extreme Inc.
Designer, architect, owner of the Level Extreme Platform
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