OR simply write VARTYPE(FormName.Grid) = 'O'
vartype is faster then type.
the drawn back is that vartype only evaluates the last statement so for example you have VARTYPE(obj1.obj2.property) and obj2 isn't an object you will get an error.

>>You should get type('objectname') = 'U' or other than 'O' if the object is not present.
>>Rajesh
>
>Unfortunately you can't just use type = "O" as a test.
>
>Try this:
>
>loObj = CREATEOBJECT("Form")
>loObj = .NULL.
>? TYPE("loObj")
>
>Gives "O", even though the object no longer exists.
>
>Either use:
>IF TYPE("loObj") = "O" AND NOT ISNULL( loObj)
>
>OR check the name property, which will only exist if the object does. Also this makes the code slightly shorter.
>
>IF TYPE("loObj.Name") = "C"