>Anyone know how to get a Julian Day (not date - that's SYS(1) I think).
>
>Apparently, it's a three digit number - that's about all I know. Before I call the client and look stupid in front of him, I thought I'd try it here first.
>
I think it's number of days from the begginig of the year, at least it was on mainframe.

 ldDate = Date()
lnJdays = ldDate - Date( Year(ldDate ),1,1) + 1
? lnJdays