Nope, this would not work. This was my original solution too.


>>Hi everyone,
>>
>>I've checked old messages, but didn't find a solution for this problem: I need to find out the number of digits in a number. Say, I have 12.3456000 - the number of digits should be seven. I don't see a simple solution, so may be you can advise?
>>
>>Thanks a lot in advance.
>
>Would this do?

lnNumber = 12.3456000
>IF AT( ".", TRANSFORM(lnNumber)) = 0
>  lnDp = 0
>ELSE
>  lnDp = LEN(TRANSFORM(lnNumber)) - AT( ".", TRANSFORM(lnNumber))
>ENDIF
>* or in one line
>lnDp = IIF( AT( ".", TRANSFORM(lnNumber)) = 0, 0, LEN(TRANSFORM(lnNumber)) - AT( ".", TRANSFORM(lnNumber)))
>