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Translating C++ FOR cycle into Foxpro code
Message
Information générale
Forum:
Visual FoxPro
Catégorie:
Autre
Divers
Thread ID:
00064105
Message ID:
00064384
Vues:
39
Gil,

I think this will give you the same result as the C code:
rhs = 0
for i = strlen( tempCustStr ) to 1 step -1
   digit = val( substr( tempCustStr, i, 1 ) ) - 48
   if ( i % 2 = 0 )
      rhs = rhs + digit
   else
      rhs = rhs + int( 2 * digit / 10 ) + ( 2 * digit ) % 10
   endif
endfor

rhs = 99 - rhs
checkdigit = int( rhs / 10 )
lastdigit = rhs % 10



>Hi everyone, I've been cracking my head trying to translate this cycle and into FP code; so far I haven't had any luck. If anybody can, please help.
>
>*Sample value:
>tempCustStr = '50400000019'
>
>****C++ code:******
>rhs = 0
>for (i = strlen(tempCustStr)-1;i>=0;i--){
> digit = *(tempCustStr + i) - '0'
> if (i % 2 == 0) {
> rhs += digit;
> //odd digits
> } else {
> rhs += (2 * digit) /10 + (2 * digit) % 10;
> }
>}
>
>rhs = 99 - rhs
>checkdigit = rhs / 10
>lastdigit = rhs % 10
>
>****My FP code: (It's not working properly)******
>rhs = 0
>i = LEN(tempCustStr) - 1
>DO WHILE i >= 0
> digit = VAL(SUBST(tempCustStr,i,1))
> IF i % 2 = 0
> rhs = rhs + digit
> ELSE
> rhs = rhs + ((2 * digit)/10) + ((2 * digit) % 10)
> ENDIF
> i = i - 1
>ENDDO
>
>rhs = 99 - rhs
>checkdigit = rhs /10
>lastdigit = rhs % 10
>
>Thanks a lot, I really appreciate any help
>
>Have a good day,
df (was a 10 time MVP)

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