Albert,

I think you've found the final missing piece of the puzzle.

>There seems to be an "off by one error" for the odd/even check. Compare:
>
>from length of string to 1
>
>>for i = strlen( tempCustStr ) to 1 step -1
>> ...
>> if ( i % 2 = 0 )
>
>from length of (string - 1) to 0
>
>>>for (i = strlen(tempCustStr)-1;i>=0;i--){
>...
>>> if (i % 2 == 0) {
>
>Therefore in VFP:
>
>if ( i % 2 > 0 )
>
>Also see Paul Vlad Tatavu's message.