I know, I just saw your post with the much quicker and more concise code. I was only posting it as an 'easy to understand' code, because I didn't know what his/her skill level was so I made it simple.
Tracy

>>Here is a long way (it can be shorter, but this is easy to understand):
>>
>>

>>SSN="2c3456789"
>>FOR i=1 TO LEN(ALLTRIM(SSN))
>>   IF !INLIST(SUBSTR(ALLTRIM(SSN),i,1),'1','2','3','4','5','6','7','8','9')
>>       MESSAGEBOX('This record has the character of '+SUBSTR(ALLTRIM(SSN),i,1),16)
>>   ELSE
>>       ?SUBSTR(ALLTRIM(SSN),i,1)
>>   ENDIF
>>ENDFOR
>>
>>

>>
>>>Some background: I have a table that is being generated on a daily basis. I need to run a few scans on the table to validate the data. One of the these checks involves making sure the social security numbers are ONLY numbers. If it does find a character in one of the fields, then I should get a message box alerting me of the error.
>>>
>>>For example, this is something along the lines of what I need to do.
>>>
>>>use export
>>>scan
>>> if (any digit of the ssn is not 1 - 9)
>>> wait window "SSN error" at 20,70
>>> endif
>>>ENDSCAN
>>>
>>>Any help would be appreciated.
>>>Thanks
>>>
>>>Ramone
>
>Tracy,
>This will be much-much slower!