David,

Thanks for the reply. That's what I thought, too, so I created an absolutely plain form, set the visible property to .F. and set step on in the first line of init(). thisform.visible is .F. in the debugger -- BUT the form is literally visible. I can see it.

Moreover, I put a checkbox on the form with the controlsource set to thisform.visible. The checkbox is initally unchecked (this is after thisform.activate() executes), but I can see the form. If I click the checkbox once, it is now checked. Twice, and the form disappears.

Clearly, this is not what I would expect. I'm sure I have some setting or other affecting this behaviour, but I have no clue what.

Joe